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Sorting value of one array according to another in Python

schedule Aug 11, 2023
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To sort the value of one array according to another in Python use the np.argsort(~) method.

Example

Consider the following NumPy arrays:

import numpy as np
x = np.array(['A','B','C','D'])
y = np.array([4,3,2,1])

Ascending order

To sort array y in ascending order and also sort array x maintaining the pair relationships between elements in the two arrays:

sort = np.argsort(y)
print(y[sort])
print(x[sort])
[1 2 3 4]
['D' 'C' 'B' 'A']

First we get the integer indices that would result in array y being sorted in ascending order, and store them to variable sort. If we actually printed this variable we would see an array [3 2 1 0]. This means that to obtain an ascending sorted copy of array y, the element at index position 3 should come first, element at index position 2 should come second and so on.

We then take sort and apply it to both y and x. For both arrays we see the printed arrays have the element that was at index position 3 (1 and 'D' respectively) appear first, then have element that was at index position 2 (2 and 'C' respectively) appear next.

Descending order

To sort array x in descending order and also sort array y maintaining the pair relationships between elements in the two arrays:

sort = np.argsort(x)
print(x[~sort])
print(y[~sort])
['D' 'C' 'B' 'A']
[1 2 3 4]

Although np.argsort(~) does not natively support descending order, you can leverage negation (~) to implement the functionality. By negating the sort array here, the index position of the highest elements will now come first and lowest elements last.

robocat
Published by Arthur Yanagisawa
Edited by 0 others
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