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Counting the occurrence of values in columns of a Pandas DataFrame

schedule Aug 10, 2023
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Counting occurrence of a single value in a column

Consider the following DataFrame:

df = pd.DataFrame({"A":["a","b","a"]})
df
A
0 a
1 b
2 a

Solution

To count the number of times the value "a" occurs in column A:

(df["A"] == "a").sum()
2

Explanation

To break this down, we are first fetching a Series of booleans where True indicates a match:

(df["A"] == "a")
0 True
1 False
2 True
Name: A, dtype: bool

Since the internal representation of a True is 1, and False is 0, we can simply take the sum of this Series to count the total occurrence:

(df["A"] == "a").sum()
2

Counting occurrence of a single value in multiple columns

Consider the following DataFrame:

df = pd.DataFrame({"A":["a","b","a"],"B":["a","a","a"]})
df
A B
0 a a
1 b a
2 a a

Solution

To get the number of "a" in each column:

(df == "a").sum()
A 2
B 3
dtype: int64

The idea is the exact same as that of the single-column case above.

Counting occurrences of multiple values in a column

Consider the following DataFrame:

df = pd.DataFrame({"A":["a","b","a","c"]})
df
A
0 a
1 b
2 a
3 c

Solution

To count the occurrences of multiple values in column A:

values = ["a","b"]
counts = df["A"].value_counts()
counts[values].sum()
3

Explanation

We first obtain a frequency count of the values in column A using Series' value_counts():

counts = df["A"].value_counts()   # returns a Series
counts
a 2
c 1
b 1
Name: A, dtype: int64

We then extract the values we are interested in using [] syntax:

counts[values]   # returns a Series
a 2
b 1
Name: A, dtype: int64

We then use the Series' sum() method:

counts[values].sum()
3

Counting the total number of occurrences

Consider the same df as above:

df = pd.DataFrame({"A":["a","b","a"],"B":["a","a","a"]})
df
A B
0 a a
1 b a
2 a a

Solution

To count the total number of "a" in df:

(df == "a").sum().sum()
5

Explanation

Once again, we first check for the presence of "a" like so:

df == "a"   # returns a Series
A B
0 True True
1 False True
2 True True

True is internally represented as a 1, while False as a 0. Taking the sum of each column yields:

(df == "a").sum()   # returns a Series
A 2
B 3
dtype: int64

This tells us that we have 2 occurrences of "a" in column A, and 3 in B. What we want is the total number so we must take a second sum:

(df == "a").sum().sum()
5
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Published by Isshin Inada
Edited by 0 others
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