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Difference between the methods mod and fmod in NumPy

schedule Aug 12, 2023
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Both mod(~) and fmod(~) methods compute the remainder of given two arrays of dividend and divisor.

What differentiates mod(~) from Numpy's fmod(~) is confusingly not whether or not one is for floating numbers; they are both capable of parsing floating numbers. The defining difference is how they handle negative numbers.

Let's take a look at a simple example.

x = [3, 8.5, -7]
np.mod(x, 3)
array([0. , 2.5, 2. ])

Here, mod(-7,3)=2, which is equivalent to Python's % implementation (-7%3=2). Also notice how 8.5, which is a floating number, was parsed correctly.

Now, let's do the same thing using the fmod method:

x = [3, 8.5, -7]
np.fmod(x, 3)
array([ 0. , 2.5, -1. ])

Here, we see that fmod(-7,3)=-1, which is a different answer from above. In fact, Numpy's fmod(~) method follows the main C library's fmod(~) implementation.

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Published by Isshin Inada
Edited by 0 others
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