Pandas DataFrame | le method
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Pandas DataFrame.le(~)
method returns a DataFrame of booleans where True
indicates an entry that is less than or equal to the specified value.
Parameters
1. other
link | scalar
or sequence
or Series
or DataFrame
The value(s) to compare with.
2. axis
link | int
or string
| optional
Whether to perform the comparison along the columns or the rows:
Axis | Description |
---|---|
| Compare each column. |
| Compare each row. |
By default, axis="columns"
.
3. level
| int
or string
| optional
The levels to perform comparison on. This is only relevant if your source DataFrame is a multi-index.
Return value
A DataFrame
of boolean
s.
Examples
Consider the following DataFrame:
df = pd.DataFrame({"A":[3,4],"B":[5,6]})df
A B0 3 51 4 6
Passing in a acalar
To check for values less than or equal to 5
in the DataFrame:
df.le(5)
A B0 True True1 True False
Comparing rows
By default, axis=1
, which means that passing in a sequence will result in a comparison with each row:
df.le([4,5]) # axis=1
A B0 True True1 True False
Here, we are comparing each row of the source DataFrame with [4,5]
. This means that we are performing the following pair-wise comparisons:
(row one) [3,5] <= [4,5] = [True, True](row two) [4,6] <= [4,5] = [True, False]
Comparing columns
By setting axis=0
, we can compare each column with the specified sequence:
df.le([4,5], axis=0)
A B0 True False1 True False
Here, we're performing the following pair-wise comparisons:
(column A) [3,4] <= [4,5] = [True, True](column B) [5,6] <= [4,5] = [False, False]
Case with missing values
Any comparison with missing values will result in False
for that entry.
Consider the following DataFrame with a missing value:
df = pd.DataFrame({"A":[3,pd.np.nan],"B":[5,6]})df
A B0 3.0 51 NaN 6
Performing a comparison yields:
df.le(5)
A B0 True True1 False False
Notice how NaN <= 5
returned False
.