
        
        
            
                
                
                    SELECT value IN (value1, value2, value3, ...);

SELECT column_name
FROM table_name
WHERE column_name IN (value1, value2, ...);

Examples

Consider the following table about some students:

student_id	fname	lname	day_enrolled	age	username
1	Sky	Towner	2015-12-03	17	stowner1
2	Ben	Davis	2016-04-20	19	bdavis2
3	Travis	Apple	2018-08-14	18	tapple3
4	Arthur	David	2016-04-01	16	adavid4
5	Benjamin	Town	2014-01-01	17	btown5

The above sample table can be created using the code here.

Basic usage

To check whether 4 is one of the listed winning numbers:


        
        
            
                
                
                    SELECT 4 IN (0, 6, 10, 14);
                
            
            +---------------------+
| 4 IN (0, 6, 10, 14) |
+---------------------+
|                   0 |
+---------------------+

Unfortunately 4 is not one of the winning numbers 0, 6, 10 or 14.

To retrieve students who are either 16, 17 or 18 years old:


        
        
            
                
                
                    SELECT *
FROM students 
WHERE age 
IN (16, 17, 18);
                
            
            +------------+----------+--------+--------------+------+----------+
| student_id | fname    | lname  | day_enrolled | age  | username |
+------------+----------+--------+--------------+------+----------+
|          1 | Sky      | Towner | 2015-12-03   |   17 | stowner1 |
|          3 | Travis   | Apple  | 2018-08-14   |   18 | tapple3  |
|          4 | Arthur   | David  | 2016-04-01   |   16 | adavid4  |
|          5 | Benjamin | Town   | 2014-01-01   |   17 | btown5   |
+------------+----------+--------+--------------+------+----------+

All students except for Ben Davis who is 19 are returned.

Published by Arthur Yanagisawa

Edited by 0 others

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Official MySQL Documentation

https://dev.mysql.com/doc/refman/8.0/en/comparison-operators.html#operator_in

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